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java faq 1 C (Programming Language) Pointer (Computer. 19/03/2010В В· Best Answer: That is because numerator is an int. Math.pow() returns a double. The error is a warning. Have fun. A char in java is 16bits jointly as an, 13/03/2008В В· possible loss of precision. Java Forums on Bytes..

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The reason for double as default literal type is that double is very much the normal floating point type in Java. I would only use float if I were dealing with a very when i try to compile this program it shows the following error : src (master)$ javac AmstrongNumber.java AmstrongNumber.java:26: error: possible loss of precision

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When Java (or another programming language) warns you that there is a possible loss of precision, they mean that you are trying to treat one type of. Well organized and easy to understand Web building tutorials with lots of examples of how to use HTML Example. Format a number into The toPrecision() method

Interesting facts about Array assignment in data-types then we will get compile-time error saying possible loss of precision. in Java with Examples; Concise answers to common basic questions about floating-point math, like

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6/01/2004В В· i have chaged them double and am now getting a differnt error where it says sum = Change (

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6/01/2004В В· i have chaged them double and am now getting a differnt error where it says sum = Change (

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here is my script: int a = 5 byte b = a ++ when i run it, my IDE gives me an error that says possible loss of precision. i do need a to be an int and b to be a byte 24/09/2010В В· I get this error when i execute the program in java: possible loss of precision found: int required: char return (c-'A'+'a'

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